浏览器打开android app

html

<a href="[scheme]://[host]/[path]?[query]">启动应用程序</a>

android

1. manifest

<activity android:name="com.ttj.v2pro.ui.TestActivity"
            android:launchMode="singleTask">

            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>

            <intent-filter>
                <action android:name="android.intent.action.VIEW" />
                <category android:name="android.intent.category.DEFAULT" />
                <category android:name="android.intent.category.BROWSABLE" />
                <data android:scheme="ttj" android:host="splash" />
            </intent-filter>

</activity>

2. activity

    override fun onNewIntent(intent: Intent?)
    {
        super.onNewIntent(intent)

        if (intent != null && intent.action == Intent.ACTION_VIEW)
        {
            val uri = intent.data
            if (uri != null)
            {
                val name = uri.getQueryParameter("name")
                toast("onNewIntent：" + name)
            }
        }
    }