第五话:函数

作者: 小猫吃鱼1990 | 来源:发表于2018-02-23 15:53 被阅读10次

    函数类型

    可以为每个参数添加类型,再为函数本身添加返回值类型。

    function add(x: number, y: number): number {

        return x + y;

    }

    let myAdd = function(x: number, y: number): number {

        return x + y;

    }

    书写完整函数类型

    1、以参数列表的形式写出参数类型,为每个参数指定一个名字和类型,名字可以和函数中的参数名字不一致,只要类型匹配即可。

    let myAdd: (x: number, y: number) => number = function(x: number, y: number): number {

        return x + y;

    }

    或者写成这样:

    let myAdd: (baseValue: number, increment: number) => number = function(x: number, y: number) {

        return x + y;

    }

    可选参数和默认参数

    1、使用?实现可选参数的功能,可选参数必须跟在必选参数后面。

    function buildName(firstName: string, lastName?: string) {

        if (lastName)

            return firstName + " " + lastName;

        else

            return firstName;

    }

    let result1 = buildName("Bob");  // works correctly now

    let result2 = buildName("Bob", "Adams", "Sr.");  // error, too many parameters

    let result3 = buildName("Bob", "Adams");  // ah, just right

    2、默认初始化值的参数,当用户没有传递这个参数或者传递的值为undefined时,参数为默认值;

        带默认初始化值得参数都是可选的,需跟在必选参数后面。

    function buildName(firstName: string, lastName = "Smith") {

        return firstName + " " + lastName;

    }

    let result1 = buildName("Bob");                  // works correctly now, returns "Bob Smith"

    let result2 = buildName("Bob", undefined);      // still works, also returns "Bob Smith"

    let result3 = buildName("Bob", "Adams", "Sr.");  // error, too many parameters

    let result4 = buildName("Bob", "Adams");        // ah, just right

    3、如果带默认初始化值得参数出现在必须参数前面,必须明确的传入undefined值来获取默认值。

    functionbuildName(firstName = "Will", lastName:string){

        return firstName + " " + lastName;

    }let result1 = buildName("Bob");                  // error, too few parameterslet result2 = buildName("Bob", "Adams", "Sr.");  // error, too many parameterslet result3 = buildName("Bob", "Adams");        // okay and returns "Bob Adams"let result4 = buildName(undefined, "Adams");    // okay and returns "Will Adams"

    剩余参数

    1、可以把所有参数收集到一个变量里,名字是在(...)后面定的名字。

    function buildName(firstName: string, ...restOfName: string[]) {

      return firstName + " " + restOfName.join(" ");

    }

    let employeeName = buildName("Joseph", "Samuel", "Lucas", "MacKinzie");

    2、带有剩余参数的函数类型定义

    function buildName(firstName: string, ...restOfName: string[]) {

      return firstName + " " + restOfName.join(" ");

    }

    let buildNameFun: (fname: string, ...rest: string[]) => string = buildName;

    this

    1、返回的函数中含有this,最好在函数定义时就制定好this的指向,使用箭头函数,this作为参数。

    interface Card {

        suit: string;

        card: number;

    }

    interface Deck {

        suits: string[];

        cards: number[];

        createCardPicker(this: Deck): () => Card;

    }

    let deck: Deck = {

        suits: ["hearts", "spades", "clubs", "diamonds"],

        cards: Array(52),

        // NOTE: The function now explicitly specifies that its callee must be of type Deck

        createCardPicker: function(this: Deck) {

            return () => {

                let pickedCard = Math.floor(Math.random() * 52);

                let pickedSuit = Math.floor(pickedCard / 13);

                return {suit: this.suits[pickedSuit], card: pickedCard % 13};

            }

        }

    }

    let cardPicker = deck.createCardPicker();

    let pickedCard = cardPicker();

    alert("card: " + pickedCard.card + " of " + pickedCard.suit);

    重载

    为同一个函数提供多个函数类型定义来进行函数重载。

    let suits = ["hearts", "spades", "clubs", "diamonds"];

    function pickCard(x: {suit: string; card: number; }[]): number;

    function pickCard(x: number): {suit: string; card: number; };

    function pickCard(x): any {

        // Check to see if we're working with an object/array

        // if so, they gave us the deck and we'll pick the card

        if (typeof x == "object") {

            let pickedCard = Math.floor(Math.random() * x.length);

            return pickedCard;

        }

        // Otherwise just let them pick the card

        else if (typeof x == "number") {

            let pickedSuit = Math.floor(x / 13);

            return { suit: suits[pickedSuit], card: x % 13 };

        }

    }

    let myDeck = [{ suit: "diamonds", card: 2 }, { suit: "spades", card: 10 }, { suit: "hearts", card: 4 }];

    let pickedCard1 = myDeck[pickCard(myDeck)];

    alert("card: " + pickedCard1.card + " of " + pickedCard1.suit);

    let pickedCard2 = pickCard(15);

    alert("card: " + pickedCard2.card + " of " + pickedCard2.suit);

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