EXCEL-SQL-group by计数

数据

数据

求属性1和属性2的差值（绝对值）小于300的数据且属性1的计数大于等于2。

---

select a.*,abs(a.属性1-a.属性2) as 差 
from  [Sheet1$a1:c] a,
(
select 属性1 from [Sheet1$a1:c] 
group by 属性1 having count(属性1)>1
) b 
where a.属性1=b.属性1 
and 
abs(a.属性1-a.属性2) <300

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解释：

• 1、先求出大于等于2的属性1有那些数据，用group by having count

select 属性1 from [Sheet1$a1:c] 
group by 属性1 having count(属性1)>1

• 2、然后将原表和上表用where做筛选，筛选出属性1计数大于1的数据，在筛选的时候，新增一个‘差值’字段计算属性1和属性2的差，同样作为筛选的条件。这样即可筛选出结果集。条件：属性1计数大于1的且属性1和属性2差值的绝对值小于300的。
  如上面代码

select a.*,abs(a.属性1-a.属性2) as 差 
from  [Sheet1$a1:c] a,
(
select 属性1 from [Sheet1$a1:c] 
group by 属性1 having count(属性1)>1    
) b 
where a.属性1=b.属性1                  --//条件1
and 
abs(a.属性1-a.属性2) <300              --//条件2

结果

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示例文件下载
链接: http://pan.baidu.com/s/1c1FnUwg 密码: seq8