swift基于HandyJSON的封装，使用范型

在之前开发中，直接是基于Codable的解析封装，然在实际项目使用中，经常碰都很多解析问题，最近改成基于HandyJSON的封装

首先定义一个基类

import UIKit 
import HandyJSON

 /**对象基类*/
class HandyBaseModel : HandyJSON{
    required init() {}
    func mapping(mapper:HelpingMapper) {
 }
}

再实现一个工具类

/// json工具类

class JsonTool:NSObject{

/**  String ---> T  */
static func toModel(_ jsonStr:String,_ modelType:T.Type) ->T? {
    if jsonStr == "" ||  jsonStr.count == 0{
        return nil
    }
    return T.deserialize(from: jsonStr)
}

/**  Any ---> T  */
static func toModel(_ data:AnyObject?,_ modelType:T.Type) ->T? {
    if let dic = data as? [String:Any] {
        return T.deserialize(from: dic)
    }
    return nil
}

/**  Dic ---> T  */
static func toModel(_ dic:[String:Any],_ modelType:T.Type) ->T?  {
    return T.deserialize(from: dic)
}

/**  Any ---> [T]  */
static func toModelArray(_ data:AnyObject?,_ modelType:T.Type) ->[T]? {
    if let dic = data as? [Any] {
        return [T].deserialize(from: dic) as? [T]
    }
    return nil
}

/**  String ---> [T]  */
public static func toModelArray(_ JSONString:String,_ type:T.Type)throws-> [T]? {
    guard let jsonData = JSONString.data(using: .utf8)else{
        return nil
    }
    if let array = try? JSONSerialization.jsonObject(with:jsonData, options: JSONSerialization.ReadingOptions()) as? [AnyObject] {
        return  JsonTool.toModelArray(arrayasAnyObject, type) ?? nil
    }
    return nil
 }

/** 对象转JSON */
static func modelToJson(_ model:HandyBaseModel?) -> String{
    if model == nil {
        print(MapError.modelToJsonFailed)
        return ""
    }
    return(model?.toJSONString())!
}

/** 对象转字典 */
static func modelToDictionary(_ model:HandyBaseModel?) -> [String:Any] {
    if model == nil{
        print(MapError.modelToJsonFailed)
        return [:]
    }
    return(model?.toJSON())!
  }
}

定义一个测试类

class TextModel:HandyBaseModel {
  var name:String?
  var age:Int?
  required init() {}
}

具体使用

let  dic = ["name":"小明","age":18] as [String:Any]
let model = JsonTool.toModel(dic,TextModel.self)
print(model?.name)