给定的队列按起始值排序

问题，给定一个无序队列，【value1,value2,value3,value4,value5】

value 数据结构如下：

    class Arrayentity {
        int start;
        int end;

        public Arrayentity() {
        }

        public Arrayentity(int start, int end) {
            this.start = start;
            this.end = end;
        }

        @Override
        public String toString() {
            return "[start:" + start + " end:" + end + "]";
        }
    }

给定队列如下：

public void initData() {


        Arrayentity a1 = new Arrayentity(1, 4);
        Arrayentity a2 = new Arrayentity(2, 6);
        Arrayentity a3 = new Arrayentity(7, 12);
        Arrayentity a4 = new Arrayentity(14, 19);
        Arrayentity a5 = new Arrayentity(22, 40);

        arrayentityList.add(a1);
        arrayentityList.add(a2);
        arrayentityList.add(a3);
        arrayentityList.add(a4);
        arrayentityList.add(a5);

    }

要求输出为：

[start:1 end:6]
[start:7 end:12]
[start:14 end:19]
[start:22 end:40]

我是这么写的

public void sort() {

        List<Arrayentity> newlist = new ArrayList<>();
        boolean needskip = false;
        List<Arrayentity> resultlist = new ArrayList<>();
        for (int i = 0; i < arrayentityList.size(); i++) {


            if (needskip) {
                needskip = false;
                continue;
            }
            Arrayentity arrayentity = new Arrayentity();
            resultlist.add(arrayentityList.get(i));
            for (int j = i + 1; j < arrayentityList.size(); j++) {
                if (arrayentityList.get(i).end >= arrayentityList.get(j).start) {

                    resultlist.remove(arrayentityList.get(i));
                    arrayentity.start = arrayentityList.get(i).start;
                    arrayentity.end = arrayentityList.get(j).end;
                    needskip = true;
                } 
            }

            if (arrayentity.start != 0 && arrayentity.end != 0) {
                resultlist.add(arrayentity);
            }

        }


        for (Arrayentity arrayentity : resultlist) {
            Log.e(TAG, "result  " + arrayentity.toString());
        }
    }