在字符串中遍历, 以当前index为中心点往外扩展。中心点为i(odd), 和中心点为i, i+1
aaa:
a a aaa a
aa aa
void expand(char *a, int left, int right, int *count)
{
while(left >=0 && a[left] == a[right]){
*count +=1;
left--;
right++;
}
}
int countSubstrings(char* s) {
int len = strlen(s);
int count = 0;
for(int i = 0; i < len; i++){
expand(s,i,i, &count);
expand(s,i,i+1, &count);
}
return count;
}
Given a string, your task is to count how many palindromi...
最大回文串正好让我回顾一下DP，动态规划比较经典的题目 总之就是一个线性规划的问题，注意递归条件： 另附一开始的办...
Given a string, your task is to count how many palindromi...
在字符串中遍历, 以当前index为中心点往外扩展。中心点为i(odd), 和中心点为i, i+1aaa:a a ...
Given a string, your task is to count how many palindromi...
起因在于写647. Palindromic Substrings时写错了，感觉跟其他回文题搞混了。特地总结一下，尤...
Given a string, your task is to count how many palindromi...
Palindromic Substrings
Given a string, your task is to count how many palindromi...
LeetCode 0647. Palindromic Substrings回文子串【Medium】【Python】...
本文标题：647. Palindromic Substrings
本文链接：https://www.haomeiwen.com/subject/wuvtbxtx.html
网友评论