(a&b)<<1 计算出所有的进位
a^b 计算出相加和
然后用a保存相加和，b保存进位，循环用和进位，直到进位为零
int getSum(int a, int b) {
int carry = 0;
while(b){
carry = (a&b)<<1;
a = a^b;
b = carry;
}
return a;
}
(a&b)<<1 计算出所有的进位
a^b 计算出相加和
然后用a保存相加和，b保存进位，循环用和进位，直到进位为零
int getSum(int a, int b) {
int carry = 0;
while(b){
carry = (a&b)<<1;
a = a^b;
b = carry;
}
return a;
}
LeetCode 371 Sum of Two Integers ========================...
D84 371. Sum of Two Integers 题目链接 371. Sum of Two Integer...
371. Sum of Two Integers【思路】： 位运算 [leetcode] 371. Sum of ...
计算a，b之和。但不能使用 + 或者 - 考点，bit运算符http://www.jianshu.com/p/7e...
(a&b)<<1 计算出所有的进位a^b 计算出相加和 然后用a保存相加和，b保存进位，循环用和进位，直到进位为零
https://leetcode.com/problems/sum-of-two-integers/descrip...
Problem Calculate the sum of two integers a and b, but yo...
Calculate the sum of two integersaandb, but you arenot al...
My SubmissionsDifficulty: EasyContributors: Admin Calcula...
感觉要用位运算，但是不知道怎么做 最优解 Java 两位单独的位相加其结果可以用异或得到, 进位可以用与得到举个例...
本文标题：371 sum of two integers
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