Array:Given a sorted array of in

Given a sorted array of integers, find the starting and ending position of a given target value.
Your algorithm's runtime complexity must be in the order of O(log n).
If the target is not found in the array, return [-1, -1].

public static int[] searchRange(int[] nums, int target) {
        int[] result = new int[2];
        result[0] = findFirst(nums, target);
        result[1] = findLast(nums, target);
        return result;
    }

    private static int findFirst(int[] nums, int target){
        int idx = -1;
        int start = 0;
        int end = nums.length - 1;
        while(start <= end){
            int mid = (start + end) / 2;
            if(nums[mid] >= target){
                end = mid - 1;
            }else{
                start = mid + 1;
            }
            if(nums[mid] == target) idx = mid;
        }
        return idx;
    }

    private static int findLast(int[] nums, int target){
        int idx = -1;
        int start = 0;
        int end = nums.length - 1;
        while(start <= end){
            int mid = (start + end) / 2;
            if(nums[mid] <= target){
                start = mid + 1;
            }else{
                end = mid - 1;
            }
            if(nums[mid] == target) idx = mid;
        }
        return idx;
    }