C# 拆分byte[]数组

将数组进行拆分，使用System.Array.Copy方法进行拆分。
比如，原数组byte[] newData = new byte[10] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };，需要拆分成2个5个元素的数组，拆分完成后，两个数组分别为{1,2,3,4,5}和{6,7,8,9,10}.

Copy有4个重载方法。个人喜欢用如图这个

byte[] newData = new byte[10] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
byte[] b = new byte[5];
byte[] c = new byte[5];
System.Array.Copy(newData, 5, c, 0, 5);
System.Array.Copy(newData, 0, b, 0, 5);    

执行完成后，b={1,2,3,4,5},c={6,7,8,9,10}

经过重写后

        /// <summary>
        /// 将一个数组拆成另外一个数组
        /// </summary>
        /// <param name="originbyte">原始数组，被拆分的数组</param>
        /// <param name="oringinstartindex">从原始数组第几个元素开始</param>
        /// <param name="destbytelength">目标数组的长度</param>
        /// <param name="destbytestartindex">目标数组开始的元素序号，默认为0</param>
        /// <returns></returns>
        public static byte[] SplitByteArray(byte[] originbyte, int oringinstartindex, int destbytelength, int destbytestartindex = 0)
        {
            byte[] result = new byte[destbytelength];
            System.Array.Copy(originbyte, oringinstartindex, result, destbytestartindex , destbytelength);
            return result;
        }