在日常开发中,经常会有计算方法调用时间的场景,我之前的做法一直是
long start =System.currentTimeMillis();
object.methodinvoke();
long end =System.currentTimeMillis();
long cost=end-start;//????
这里真的有个坑!!!!!!!!!
来看看currentTimeMillis()这个方法的源码注释,这个方法返回的是当前时间的微秒数。恰恰因为返回的是微秒数,而这个值的颗粒度取决于底层的操作系统,所以就可能会很大。例如,很多操作系统的时间颗粒度是10微妙。而且这个时间又可能受NTP影响而产生微调,从而导致时间很不准确。
综上,这种写法是不严谨的。
/**
* Returns the current time in milliseconds. Note that
* while the unit of time of the return value is a millisecond,
* the granularity of the value depends on the underlying
* operating system and may be larger. For example, many
* operating systems measure time in units of tens of
* milliseconds.
*
* <p> See the description of the class <code>Date</code> for
* a discussion of slight discrepancies that may arise between
* "computer time" and coordinated universal time (UTC).
*
* @return the difference, measured in milliseconds, between
* the current time and midnight, January 1, 1970 UTC.
* @see java.util.Date
*/
public static native long currentTimeMillis();
正确的操作应该是这个样子的:
long start =System.nanoTime();
object.methodinvoke();
long end =System.nanoTime();
long cost=end-start;// 为什么是准确的呢?
来看看nanoTime()的源码注释,这个方法返回的是JVM运行的纳秒数,它只依赖与当前的jvm,并且不会出现同步的情况,所以是准确的。
/**
* Returns the current value of the running Java Virtual Machine's
* high-resolution time source, in nanoseconds.
*
* <p>This method can only be used to measure elapsed time and is
* not related to any other notion of system or wall-clock time.
* The value returned represents nanoseconds since some fixed but
* arbitrary <i>origin</i> time (perhaps in the future, so values
* may be negative). The same origin is used by all invocations of
* this method in an instance of a Java virtual machine; other
* virtual machine instances are likely to use a different origin.
*
* <p>This method provides nanosecond precision, but not necessarily
* nanosecond resolution (that is, how frequently the value changes)
* - no guarantees are made except that the resolution is at least as
* good as that of {@link #currentTimeMillis()}.
*
* <p>Differences in successive calls that span greater than
* approximately 292 years (2<sup>63</sup> nanoseconds) will not
* correctly compute elapsed time due to numerical overflow.
*
* <p>The values returned by this method become meaningful only when
* the difference between two such values, obtained within the same
* instance of a Java virtual machine, is computed.
*
* <p> For example, to measure how long some code takes to execute:
* <pre> {@code
* long startTime = System.nanoTime();
* // ... the code being measured ...
* long estimatedTime = System.nanoTime() - startTime;}</pre>
*
* <p>To compare two nanoTime values
* <pre> {@code
* long t0 = System.nanoTime();
* ...
* long t1 = System.nanoTime();}</pre>
*
* one should use {@code t1 - t0 < 0}, not {@code t1 < t0},
* because of the possibility of numerical overflow.
*
* @return the current value of the running Java Virtual Machine's
* high-resolution time source, in nanoseconds
* @since 1.5
*/
public static native long nanoTime();
另外,在计算当前日期的时候是要使用currentTimeMillis()的,因为它是相对于 midnight, January 1, 1970 UTC的时间长度,而nanoTime()是相对于jvm的运行时间,这个时间是不确定的。
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