一、读程序,总结程序的功能:
numbers=1
for i in range(0,20):
numbers*=2
print(numbers)
求2的20次方的结果
summation=0
num=1
while num<=100:
if (num%3==0 or num%7==0) and num%21!=0:
summation += 1
num+=1
print(summation)
记录1~100中能被3或7整除但不能被21整除的数的个数
二、编程实现(for和while各写⼀遍):
- 求1到100之间所有数的和、平均值
for 循环
sum = 0
for x in range(1,101):
sum+=x
print(sum,sum/100)
while循环
num = 0
sum =0
while num <=100:
sum+=num
num+=1
print(sum,sum/100)
- 计算1-100之间能3整除的数的和
for循环
sum = 0
for x in range(1,101):
if x %3 == 0:
sum+=x
print(sum)
while 循环
num=0
sum=0
while num<=100:
if num % 3 ==0:
sum+=num
num+=1
print(sum)
- 计算1-100之间不能被7整除的数的和
for 循环
for x in range(1,101):
if x % 7 != 0 :
sum += x
print(sum)
while 循环
num = 0
sum = 0
while num <= 100:
if num % 7 !=0:
sum += num
num += 1
print(sum)
三、
- 求斐波那契数列中第n个数的值:1,1,2,3,5,8,13,21,34....
num1 = 1 #第n-1个数
num2 = 1# 第n-2个数
num = int(input('你想查询第几位数:'))
for num in range (3,num+1):
num3=num1+num2
num1,num2=num3,num1
print('第%d个数是%d'%(num,num3)
- 判断101-200之间有多少个素数,并输出所有素数。判断素数的⽅法:⽤⼀个数分别除2到sqrt(这个数),如果能被整除,则表明此数不是素数,反之是素数
num = 0
for x in range (101,201):
for y in range (2,x):
if x % y == 0 :
break
else:
num += 1
print(x)
print(num)
- 打印出所有的⽔仙花数,所谓⽔仙花数是指⼀个三位数,其各位数字⽴⽅和等于该数本身。例如:153是
⼀个⽔仙花数,因为153 = 1^3 + 5^3 + 3^3
方法一:
for num in range (100,1000):
if int(str(num)[0])**3+int(str(num)[1])**3+int(str(num)[2])**3 == num:
print('%d是水仙花数'%num)
方法二:
geiwei = num % 10
shiwei = num % 100//10
baiwei=num//100
for num in range (100,1000):
geiwei = num % 10
shiwei = num % 100//10
baiwei=num//100
if gewei**3+shiwei**3+baiwei**3 == num:
print('%d是水仙花数'%num)
- 有⼀分数序列:2/1,3/2,5/3,8/5,13/8,21/13...求出这个数列的第20个分数
分⼦:上⼀个分数的分⼦加分⺟ 分⺟: 上⼀个分数的分⼦ fz = 2 fm = 1 fz+fm / fz
fen_zi=2
fen_mu=1
for x in range(2,21):
fen_zi,fen_mu=fen_zi+fen_mu,fen_zi
print('%d/%d'%(fen_zi,fen_mu))
- 给⼀个正整数,要求:1、求它是⼏位数 2.逆序打印出各位数字
num = input('请输入一个正整数:')
print(len(num),num[::-1])
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