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PAT-A 1001 A+B Format(C语言)

PAT-A 1001 A+B Format(C语言)

作者: dk_qi | 来源:发表于2019-01-01 15:33 被阅读0次

题目

链接:PAT (Advanced Level) Practice 1001 A+B Format

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −10^6​​ ≤a,b≤10^6​​ . The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991


思路

题目大意是输入两个取值范围在-10^610^6之间的整数,求它们的和,并输出,输出格式要每隔3位数输出一个逗号,如示例。
所以思路就是分多次输出,因为两数和最大也只有7位数,所以穷举各种可能性即可。


代码

#include<stdio.h>

int main(){
  int a, b, sum;
  scanf("%d %d", &a, &b);
  sum = a + b;
  if(sum < 0){
    printf("-");
    sum = -sum;
  }
  
  if(sum >= 1000000){      //当位数大于6时
    printf("%d,%03d,%03d", sum / 1000000, sum % 1000000 / 1000, sum % 1000);
  }
  else if(sum >= 1000){    //当位数大于3小于6时
    printf("%d,%03d", sum / 1000, sum % 1000);
  }
  else{                    //当位数小于等于3时
    printf("%d", sum);
  }
  return 0;
}

---END---

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