iOS字符串数组转NSDictionary操作笔记

使用场景:
app分享之后,其他用户点击分享链接,进行app下载,在下载之后打开app之后会将分享链接中的一些参数带进app,app根据这些参数来做一些业务处理.
这里是获取到的数据格式[appdata paramsData]的示例,实际的类型是字符串

userid=info&username=valueName&useravatar=avatar

为了方便使用和解析,开发者希望拿到的数据格式应该为

{
      "userid":"info",
      "username":"valueName",
      "useravatar":"avatar"
}

为了获取如上所示的数据类型,需要做一些操作

方案一 :

第一步: 将字符串中的"&"符号替换成"=",并根据"="对字符串进行分割,分割结果为字符串数组

    NSString * comString = [string stringByReplacingOccurrencesOfString:@"&" withString:@"="];
    NSArray * array = [comString componentsSeparatedByString:@"="];

第二步:数组转字典

    NSMutableDictionary * dicInfo = [NSMutableDictionary dictionaryWithCapacity:0];
    for (int i = 0; i < array.count - 1; i += 2) {
        NSString * stringKey = array[i];
        NSString * stringValue = array[i + 1];
        [dicInfo setValue:stringValue forKey:stringKey];
    }

方案一所有的实现代码:

-(NSDictionary *)dicWithAndEqualString:(NSString *)string {
    
    NSString * comString = [string stringByReplacingOccurrencesOfString:@"&" withString:@"="];
    NSLog(@"替换字&符串之后的str=%@",comString);
    NSArray * array = [comString componentsSeparatedByString:@"="];
    NSLog(@"分割之后的arr=%@",array);
    NSMutableDictionary * dicInfo = [NSMutableDictionary dictionaryWithCapacity:0];
    for (int i = 0; i < array.count - 1; i += 2) {
        NSString * stringKey = array[i];
        NSString * stringValue = array[i + 1];
        [dicInfo setValue:stringValue forKey:stringKey];
    }
    NSLog(@"得到的结果字典=%@",dicInfo);
    return dicInfo;
}

方案一打印结果:

2021-09-09 17:45:47.782308+0800 raceme[2641:1860334] 初始的字符串str = userid=info&username=valueName&useravatar=avatar
2021-09-09 17:45:47.782402+0800 raceme[2641:1860334] 替换字&符串之后的str=userid=info=username=valueName=useravatar=avatar
2021-09-09 17:45:47.782485+0800 raceme[2641:1860334] 分割之后的arr=(
    userid,
    info,
    username,
    valueName,
    useravatar,
    avatar
)
2021-09-09 17:45:47.782555+0800 raceme[2641:1860334] 得到的结果字典={
    useravatar = avatar;
    userid = info;
    username = valueName;
}

方案二:

第一步:将字符串根据"="和"&"分割成数组,这里因为使用componentsSeparatedByCharactersInSet方法分割字符串会出现空字符串@"",因此需要对得到的数组字符串中包含的空值@""进行去除操作,防止下一步的key和value值因为空值导致赋值错乱

    NSMutableArray * array = [NSMutableArray arrayWithArray:[string componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@"=&"]]];
    [array removeObject:@""];

第二步:字典转数数组

    NSMutableDictionary * dicInfo = [NSMutableDictionary dictionaryWithCapacity:0];
    for (int i = 0; i < array.count - 1; i += 2) {
        NSString * stringKey = array[i];
        NSString * stringValue = array[i + 1];
        [dicInfo setValue:stringValue forKey:stringKey];
    }

方案二所有的实现代码:

-(NSDictionary *)dicWithAndEqualAnotherString:(NSString *)string {
    
    NSMutableArray * array = [NSMutableArray arrayWithArray:[string componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@"=&"]]];
    NSLog(@"根据=&字符分割之后的arr=%@",array);
    [array removeObject:@""];
    NSLog(@"去掉空字符串之后arr=%@",array);

    NSMutableDictionary * dicInfo = [NSMutableDictionary dictionaryWithCapacity:0];
    for (int i = 0; i < array.count - 1; i += 2) {
        NSString * stringKey = array[i];
        NSString * stringValue = array[i + 1];
        [dicInfo setValue:stringValue forKey:stringKey];
    }
    NSLog(@"得到到的结果字典=%@",dicInfo);

    return dicInfo;
}

方案二的代码打印结果

2021-09-09 17:44:29.774279+0800 raceme[2639:1859818] 初始的字符串str = userid=info&username=valueName&useravatar=avatar
2021-09-09 17:44:29.774424+0800 raceme[2639:1859818] 根据=&字符分割之后的arr=(
    userid,
    info,
    username,
    valueName,
    useravatar,
    avatar
)
2021-09-09 17:44:29.774481+0800 raceme[2639:1859818] 去掉空字符串之后arr=(
    userid,
    info,
    username,
    valueName,
    useravatar,
    avatar
)
2021-09-09 17:44:29.774551+0800 raceme[2639:1859818] 得到到的结果字典={
    useravatar = avatar;
    userid = info;
    username = valueName;
}