Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
思路:
基本的链表操作题,用迭代方法实现,首先建立dummy节点,最后注意转换相邻链表后的链表连接。
var swapPairs = function(head) {
var dummy=new ListNode(-1);
var pre=dummy;
dummy.next=head;
while(pre.next && pre.next.next){
var t=pre.next.next;
pre.next.next=t.next;
t.next=pre.next;
pre.next=t;
pre=t.next;
}
return dummy.next;
};
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