ZOJ1094-Matrix Chain Multiplicat
作者:
Jiafu | 来源:发表于
2017-09-29 14:01 被阅读0次#encoding=utf8
import sys
# 存储矩阵,每个矩阵是一个三元组
matrixs = []
def func(matrix_express):
if len(matrix_express) == 0:
return 0
# 用于计算表达式的栈
stack = []
# 乘法次数
time_count = 0
for symbol in matrix_express:
if symbol == '(':
stack.append(symbol)
elif symbol == ')':
matrix_b = stack.pop()
matrix_a = stack.pop()
# 弹出(
stack.pop()
# 如果两个矩阵可相乘
if matrix_a[2] == matrix_b[1]:
time_count += matrix_a[1] * matrix_a[2] * matrix_b[2]
stack.append(('', matrix_a[1], matrix_b[2]))
else:
return 'error'
else:
for m in matrixs:
if m[0] == symbol:
stack.append(m)
break
else:
raise Exception('matrix not found')
return time_count
if __name__ == '__main__':
is_first_line = True
for line in sys.stdin:
if is_first_line:
n = int(line)
is_first_line = False
continue
if n > 0:
matrix = line.split()
matrixs.append((matrix[0], int(matrix[1]), int(matrix[2])))
n -= 1
continue
print func(line.split('\n')[0])
本文标题:ZOJ1094-Matrix Chain Multiplicat
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