c++11 STL和simulink自动生成代码--Apple的

c++11 STL和simulink自动生成代码--Apple的学习笔记

目的：

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为了学习c++11 STL和simulink自动生成代码
c++11集成后的vscode工程及matlab 2015b的工程都上传到了我的github。
https://github.com/AppleCai/myprinter

立项：

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我需要设计一个练手的小项目。私人定制播放器

需求：

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能将txt每行的内容按控制命令输出。
一个开关按钮(control[0])：1代表开，0代表关
一个暂停按钮(control[1])：1代表暂停，0代表继续
一个向上按钮(control[2])：1代表向上，0代表不变
一个向下按钮(control[3])：1代表向下，0代表不变
总共包括4个状态（open:printState=1;close:printState=0;run:printState=2;suspend:printState=3)

设计：

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思路是这样的，从txt中读取需要打印的内容。从doc窗口读取4个控制指令，来控制当前打印第几项内容。而控制功能使用stateflow状态机实现，通过simulink自动生成的代码集成到主函数中，实现将结果输出到doc窗口。

simulink设计：

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simulink stateflow.png

c++11主函数：

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/*
 * @Descripttion: my printer
 * @version: V1.0
 * @Author: AppleCai
 * @Date: 2019-11-02 13:38:13
 * @LastEditors: AppleCai
 * @LastEditTime: 2019-11-02 17:13:29
 */
#include <iostream> // For standard streams
#include <fstream>  // For file streams
#include <iterator> // For iterators and begin() and end()
#include <string>   // For string class
#include <vector>   // For vector containers
#include "myprinter.h"                 // Model's header file
#include "rtwtypes.h"
static myprinterModelClass rtObj;      // create simulink object
int main()
{
  // simulink initialization
  rtObj.initialize();
  // read txt file
  std::string file_in{"D:/ws/readcfg/mylist.txt"};
  std::ifstream in{file_in};
  if (!in)
  {
    std::cerr << file_in << " not open." << std::endl;
    exit(1);
  }
  std::vector<std::string> words{std::istream_iterator<std::string>(in), std::istream_iterator<std::string>()};
  // print all the lines in txt
  std::copy(std::begin(words), std::end(words), std::ostream_iterator<std::string>{std::cout, ","});
  std::cout << std::endl;
  // close txt file
  in.close(); // Close the file
  
  std::vector<std::string> controls;
  std::string control;
  std::int8_t myindex = 0;
  // call simulink function, let it into initial state
  rtObj.step();
  // main function, use ctrl+C for end
  while(true)
  {
    // get control value, if empty then beark
    while (true)
    {
      myindex++;
      std::cout << "Enter control value " << std::to_string(myindex) << ",empty line to end:";
      std::getline(std::cin, control, '\n');
      if (control.empty())
        break;
      controls.emplace_back(control);
    }
    std::cout<<std::endl;
    myindex = 0;

    // bind the control value to the input of simulink
    g_bl_BtnOpen = std::stoi(controls[0]);
    g_bl_BtnSuspend =std::stoi(controls[1]);
    g_bl_BtnPrevious =std::stoi(controls[2]);
    g_bl_BtnNext =std::stoi(controls[3]);
    // run stateflow
    rtObj.step();
    // clear the control command
    controls.clear(); 
    // print out the result
    if (g_u8_printState == 0)
    {
      std::cout <<"print out:close"<<std::endl;
    }
    else if(g_u8_printState == 3)
    {
      std::cout <<"print out:suspend"<<std::endl;
    }
    else
    {
      std::cout <<"print out:"<<words[g_u8_n]<<std::endl;
    }
  }
}

遇到的问题：

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1. simulink中全局变量的设置。我设置完变量后生成代码放入了一个结构体中？

   解决方法：通过修改信号线属性中Code Generation中Storage class:选择ExportedGlobal

2. 输入控制命令1001期望输出1-cd，但是结果输出close。

   解决方法：原因是matlab的step()函数需要先调用一次，因为matlab有状态机的初始化状态。【由于我open状态里面有run和suspend，所以又存在这样的初始化状态问题，这类问题我暂时想到的就是将open状态删除，不要有子状态。将来再看看有没有其他解决方法】

   
   初始状态的问题.png

3. 输入控制命令在变，但是输出不符合预期，看上去保持了第一次的输入命令。

   解决方法：用完一次指令后，需要添加controls.clear(); 来清空控制命令，重新使用下一次的指令。

代码运行结果：

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1-a,2-cd,3-ef,4-g,5-h,6-ijk,7-lm,8-op,9-q,10-rs,
Enter control value 1,empty line to end:1
Enter control value 2,empty line to end:0
Enter control value 3,empty line to end:0
Enter control value 4,empty line to end:1
Enter control value 5,empty line to end:

print out:1-a
Enter control value 1,empty line to end:1
Enter control value 2,empty line to end:0
Enter control value 3,empty line to end:0
Enter control value 4,empty line to end:1
Enter control value 5,empty line to end:

print out:2-cd
Enter control value 1,empty line to end:1
Enter control value 2,empty line to end:0
Enter control value 3,empty line to end:1
Enter control value 4,empty line to end:0
Enter control value 5,empty line to end:

print out:1-a
Enter control value 1,empty line to end:1
Enter control value 2,empty line to end:1
Enter control value 3,empty line to end:0
Enter control value 4,empty line to end:0
Enter control value 5,empty line to end:

print out:suspend
Enter control value 1,empty line to end:1
Enter control value 2,empty line to end:0
Enter control value 3,empty line to end:0
Enter control value 4,empty line to end:0
Enter control value 5,empty line to end:

print out:1-a
Enter control value 1,empty line to end:1
Enter control value 2,empty line to end:0
Enter control value 3,empty line to end:0
Enter control value 4,empty line to end:1
Enter control value 5,empty line to end:

print out:2-cd
Enter control value 1,empty line to end:1
Enter control value 2,empty line to end:0
Enter control value 3,empty line to end:0
Enter control value 4,empty line to end:1
Enter control value 5,empty line to end:

print out:3-ef
Enter control value 1,empty line to end:0
Enter control value 2,empty line to end:0
Enter control value 3,empty line to end:0
Enter control value 4,empty line to end:0
Enter control value 5,empty line to end:

print out:close
Enter control value 1,empty line to end:^C