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python+django 设计一个接口返回json

python+django 设计一个接口返回json

作者: 一大碗面丶 | 来源:发表于2018-10-30 12:53 被阅读0次

废话不多说,今天介绍一个用来写json接口的第三方库djangorestframework
下载地址:http://www.django-rest-framework.org
终端指令安装:

pip install djangorestframework

修改settings.py文件

INSTALLED_APPS = [
    'django.contrib.admin',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.messages',
    'django.contrib.staticfiles',
    "tcapp",
    'rest_framework_swagger',//新增
    'rest_framework',//新增
]

数据库里的模型转json
python3.5自带json包 import json即可
也可以用模型序列化django-simple-serializer这个库来做Model->Json
终端指令:

pip install django-simple-serializer

接下来开始写一个返回json的接口
在项目中,打开views.py文件。

# -*- coding: utf-8 -*-
from __future__ import unicode_literals

from django.shortcuts import render
from rest_framework.views import APIView
from dss.Serializer import serializer
from django.http import HttpResponse, HttpRequest
from tcapp.models import itemsPost

# Create your views here.

def response_as_json(data, foreign_penetrate=False):
    jsonString = serializer(data=data, output_type="json", foreign=foreign_penetrate)
    response = HttpResponse(
            # json.dumps(dataa, cls=MyEncoder),
            jsonString,
            content_type="application/json",
    )
    response["Access-Control-Allow-Origin"] = "*"
    return response

def json_response(data, code=200, foreign_penetrate=False, **kwargs):
    data = {
        "code": code,
        "msg": "成功",
        "data": data,
    }
    return response_as_json(data, foreign_penetrate=foreign_penetrate)

def json_error(error_string="", code=500, **kwargs):
    data = {
        "code": code,
        "msg": error_string,
        "data": {}
    }
    data.update(kwargs)
    return response_as_json(data)

JsonResponse = json_response
JsonError = json_error
class ReturnJson(APIView):

    def get(self, request, *args, **kwargs):
        return JsonResponse(itemsPost.objects.all())

逻辑写好, 在urls.py中添加此接口

from django.conf.urls import url
from django.contrib import admin
from tcapp.views import ReturnJson

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^api', ReturnJson.as_view()),
]

运行项目
游览器中输入

http://127.0.0.1:8000/api

游览器中会返回数据库模型转换的json数据

报错:ImportError: No module named rest_framework_swagger
解决:缺少插件,指令安装:

sudo pip install django-rest-swagger

感觉对你有帮助,点下订阅再走哦!

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