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LEETCODE 88. Merge Sorted Array

LEETCODE 88. Merge Sorted Array

作者: 我真的不是狼人 | 来源:发表于2017-07-03 01:16 被阅读0次

    题意:Given two sorted integer arrays A and B, merge B into A as one sorted array.

    解题思路:归并排序的归并这一步的实现,原理很多地方都有。使用一个tmp临时数组进行归并

    class Solution:

    # @param A  a list of integers

    # @param m  an integer, length of A

    # @param B  a list of integers

    # @param n  an integer, length of B

    # @return nothing

    def merge(self, A, m, B, n):

    tmp = [0 for i in range(m + n)]

    i = 0; j = 0; k = 0

    while i < m and j < n:

    if A[i] <= B[j]:

    tmp[k] = A[i]; i += 1

    else:

    tmp[k] = B[j]; j += 1

    k += 1

    if i == m:

    while k < m + n:

    tmp[k] = B[j]; k += 1; j += 1

    else:

    while k < m + n:

    tmp[k] = A[i]; i += 1; k += 1

    for i in range(0, m + n):

    A[i] = tmp[i]

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