map()函数 Python

map(function, iterable, ...)

class map(object)
 |  map(func, *iterables) --> map object
 |
 |  Make an iterator that computes the function using arguments from
 |  each of the iterables.  Stops when the shortest iterable is exhausted.
 |
 |  Methods defined here:
 |
 |  __getattribute__(self, name, /)
 |      Return getattr(self, name).
 |
 |  __iter__(self, /)
 |      Implement iter(self).
 |
 |  __next__(self, /)
 |      Implement next(self).
 |
 |  __reduce__(...)
 |      Return state information for pickling.
 |
 |  ----------------------------------------------------------------------
 |  Static methods defined here:
 |
 |  __new__(*args, **kwargs) from builtins.type
 |      Create and return a new object.  See help(type) for accurate signature.

据提供的函数对指定序列做映射。
把可迭代数据集合中每个元素调用function，返回值形成新的集合。

>>>def square(x) :            # 计算平方数
...     return x ** 2
... 
>>> map(square, [1,2,3,4,5])   # 计算列表各个元素的平方
[1, 4, 9, 16, 25]
>>> map(lambda x: x ** 2, [1, 2, 3, 4, 5])  # 使用 lambda 匿名函数
[1, 4, 9, 16, 25]
 
# 提供了两个列表，对相同位置的列表数据进行相加
>>> map(lambda x, y: x + y, [1, 3, 5, 7, 9], [2, 4, 6, 8, 10])
[3, 7, 11, 15, 19]


>>> list(map(lambda x : x / 2,range(1,6)))
[0.5, 1.0, 1.5, 2.0, 2.5]

Reference

[1] https://www.runoob.com/python/python-func-map.html