21. 合并两个有序链表
作者:
Andysys | 来源:发表于
2019-12-29 00:21 被阅读0次 // 递归
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1 == null) {
return l2;
}
if (l2 == null) {
return l1;
}
if (l1.val < l2.val) {
l1.next = mergeTwoLists(l1.next, l2);
return l1;
} else {
l2.next = mergeTwoLists(l1, l2.next);
return l2;
}
}
// 迭代
public ListNode mergeTwoLists2(ListNode l1, ListNode l2) {
ListNode head = new ListNode(0);
ListNode prev = head;
while (l1 != null && l2 != null) {
if (l1.val < l2.val) {
prev.next = l1;
l1 = l1.next;
} else {
prev.next = l2;
l2 = l2.next;
}
prev = prev.next;
}
prev.next = l1 == null ? l2 : l1;
return head.next;
}
本文标题:21. 合并两个有序链表
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