Given a set of distinct integers, nums, return all possible subsets (the power set).
Note: The solution set must not contain duplicate subsets.
Example:
Input:nums = [1,2,3]Output:[ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], []]
有个我比较无语的地方,就是加上了nums.length == 0 的判断之后,虽然执行时间从1ms变成了0ms,但是成绩从50%到了100%,说明leetcode这个题目的测试数据给的太少了呀
class Solution {
public List<List<Integer>> subsets(int[] nums) {
List<List<Integer>> res = new LinkedList<>();
if (nums.length == 0) return res;
List<Integer> cur = new ArrayList<>();
backtrace(cur, res, nums, 0);
return res;
}
private void backtrace(List<Integer> cur, List<List<Integer>> res, int[] nums, int start) {
res.add(new ArrayList<>(cur));
for (int i = start; i < nums.length; i++) {
cur.add(nums[i]);
backtrace(cur, res, nums, i + 1);
cur.remove(cur.size() - 1);
}
}
}
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