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2019-08-27 A1035 Password

2019-08-27 A1035 Password

作者: JO炮 | 来源:发表于2019-08-28 10:27 被阅读0次

    这道题对我来说有些困难,用了很长时间(并看了柳神的代码)才解决,下面这个blog是对vector容器的各种函数的介绍:
    https://blog.csdn.net/ak201605050122/article/details/80225297

    #include <iostream>
    #include <vector>
    using namespace std;
    
    int main() {
        vector<string> v;
        int n;
        scanf("%d", &n);
        for(int j = 0; j < n; j++){
            string name, s;
            cin >> name >> s;
            int flag = 0;
            for(int i = 0; i < s.length(); i++){
                switch(s[i]) {
                    case '1' : s[i] = '@'; flag = 1; break;
                    case '0' : s[i] = '%'; flag = 1; break;
                    case 'l' : s[i] = 'L'; flag = 1; break;
                    case 'O' : s[i] = 'o'; flag = 1; break;
                }
            }
            if(flag){
                string temp = name + " " + s;
                v.push_back(temp);
            }
        }
            int cnt = v.size();
            if(cnt != 0){
                printf("%d\n", cnt);
                for(int i = 0; i < cnt; i++)
                    cout << v[i] << endl;
            } else if(n == 1) {
                printf("There is 1 account and no account is modified");
            } else {
                printf("There are %d accounts and no account is modified", n);
            }
        
        return 0;
    }
    

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