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.net web api json参数错误的json格式和返回结

.net web api json参数错误的json格式和返回结

作者: 吉凶以情迁 | 来源:发表于2022-09-06 08:45 被阅读0次

经过测试发现 要获取 详细信息需要通过
Microsoft.AspNetCore.Mvc.ValidationProblemDetails(context.ModelState)解析,

builder.Services.AddControllers().ConfigureApiBehaviorOptions(setupAction => setupAction.InvalidModelStateResponseFactory = context =>
{
    var problemDetail = new Microsoft.AspNetCore.Mvc.ValidationProblemDetails(context.ModelState)
    {
        Type = "无所谓",
        Title = "数据验证失败",
        Status = StatusCodes.Status200OK,
        Detail = "请看详细说明",
        Instance = context.HttpContext.Request.Path
    };/*    var problemDetail = new Microsoft.AspNetCore.Mvc.ValidationProblemDetails(context.ModelState)
    {
        Type = "无所谓",
        Title = "数据验证失败",
        Status = StatusCodes.Status200OK,
        Detail = "请看详细说明",
        Instance = context.HttpContext.Request.Path
    };*/
    int count=problemDetail.Errors.Count;
   
    StringBuilder sb = new StringBuilder();
    sb.Append("数据验证错误");

    foreach (KeyValuePair<string, string[]> kv in problemDetail.Errors)

    {

        StringBuilder s1 = new StringBuilder();
        for(int i=0;i< kv.Value.Length; i++)
        {
            s1.Append(kv.Value[i]+" ");

        }
        sb.Append($"参数:{kv.Key}错误,"+s1.ToString()+" ");
        //Console.WriteLine(kv.Key + kv.Value);

    }
    /*  for(int i = 0; i < count; i++)
      {
          problemDetail.Errors.Keys.for
          sb.Append(problemDetail.Errors[]);
      }*/
    var result=new
    {
        code = -1,
        Status = StatusCodes.Status200OK,
        msg = sb.ToString()
    };
    problemDetail.Extensions.Add("traceId", context.HttpContext.TraceIdentifier);
    return new Microsoft.AspNetCore.Mvc.JsonResult(result);
    /*    return new Microsoft.AspNetCore.Mvc.UnprocessableEntityObjectResult(problemDetail)
    {
        ContentTypes = { "application/json" }
    };*/
}); 

最后返回 jsonresult而不是UnprocessableEntityObjectResult否则结果代码并不是200,

image.png

下面地址实际上返回的是模拟默认的结果实现

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