- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
- C语言编程 C Language Programming - 0
编程题0005 (from Programming Teaching Assistant (PTA))
字符串循环左移
输入一个字符串和一个非负整数N,要求将字符串循环左移N次。
输入格式:
输入在第1行中给出一个不超过100个字符长度的、以回车结束的非空字符串;第2行给出非负整数N。
输出格式:
在一行中输出循环左移N次后的字符串。
输入样例:
Hello World!
2
输出样例:
llo World!He
Answer:
#include <stdio.h>
#include <string.h>
void main(){
char str[101], tmp;
int ans = 0, len = 0, i = 0, j = 0, tim = 0;
gets(str);
scanf("%d",&ans);
len = strlen(str);
if (len==0||ans==0||ans%len==0){
printf("%s",str);
return;
}
ans = ans%len;
if(ans==0){
i=0;
j=ans;
while(j<len){
tmp = str[i];
str[i] = str[j];
str[j] = tmp;
i++;
j++;
}
}else{
j = ans - 1;
while(i<j){
tmp = str[i];
str[i] = str[j];
str[j] = tmp;
i++;
j--;
}
i=0;
j=ans;
while(j<len){
tmp = str[i];
str[i] = str[j];
str[j] = tmp;
i++;
j++;
}
j-=len%ans+1;
while(i<j){
tmp = str[i];
str[i] = str[j];
str[j] = tmp;
i++;
j--;
}
}
printf("%s",str);
}
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