题目链接:
https://leetcode-cn.com/problems/kids-with-the-greatest-number-of-candies/
我的答案:
class Solution {
public List<Boolean> kidsWithCandies(int[] candies, int extraCandies) {
List<Boolean> mylist=new ArrayList<Boolean>();
//获取最大值
int max=0;
for (int i = 0; i < candies.length; i++) {
if(candies[i]>max) {
max=candies[i];
}
}
//如果加上额外糖果大于等于最大值,那么在mylist加入true,否则加入false
for (int i = 0; i < candies.length; i++) {
if((candies[i]+extraCandies)>=max) {
mylist.add(true);
}else {
mylist.add(false);
}
}
return mylist;
}
}
总结:
1.见注释
2.list使用增强for循环可以遍历
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