pycurl.so: undefined symbol 解决方法

使用yum install 包时出现的undefined symbol问题：

yum install libatomic1 -y
There was a problem importing one of the Python modules
required to run yum. The error leading to this problem was:

   /usr/lib64/python2.7/site-packages/pycurl.so: undefined symbol: CRYPTO_num_locks

Please install a package which provides this module, or
verify that the module is installed correctly.

It's possible that the above module doesn't match the
current version of Python, which is:
2.7.5 (default, Aug  4 2017, 00:39:18) 
[GCC 4.8.5 20150623 (Red Hat 4.8.5-16)]

If you cannot solve this problem yourself, please go to 
the yum faq at:
  http://yum.baseurl.org/wiki/Faq

看静态链接库的情况：

# ldd /usr/lib64/python2.7/site-packages/pycurl.so 
        linux-vdso.so.1 =>  (0x00007ffd487c1000)
        libcurl.so.4 => /usr/local/lib/libcurl.so.4 (0x00007f89c19e1000)(此处的问题)
        libpython2.7.so.1.0 => /lib64/libpython2.7.so.1.0 (0x00007f89c1615000)
        libpthread.so.0 => /lib64/libpthread.so.0 (0x00007f89c13f9000)
        libc.so.6 => /lib64/libc.so.6 (0x00007f89c102c000)
        libz.so.1 => /lib64/libz.so.1 (0x00007f89c0e16000)
        libdl.so.2 => /lib64/libdl.so.2 (0x00007f89c0c12000)
        libutil.so.1 => /lib64/libutil.so.1 (0x00007f89c0a0f000)
        libm.so.6 => /lib64/libm.so.6 (0x00007f89c070d000)
        /lib64/ld-linux-x86-64.so.2 (0x00007f89c1e44000)

libcurl.so.4在哪里：

locate libcurl.so.4
/opt/soft/curl-7.46.0/lib/.libs/libcurl.so.4
/opt/soft/curl-7.46.0/lib/.libs/libcurl.so.4.4.0
/usr/lib64/libcurl.so.4
/usr/lib64/libcurl.so.4.3.0
/usr/local/lib/libcurl.so.4
/usr/local/lib/libcurl.so.4.4.0

# 删掉有问题的lib库
rm /usr/local/lib/libcurl.so.4

# 重新link
ln -s /usr/lib64/libcurl.so.4.3.0 /usr/lib/libcurl.so.4