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Swift(iOS 9 Xcode7)   一个app打开另一个

Swift(iOS 9 Xcode7)   一个app打开另一个

作者: NoExcuse | 来源:发表于2015-10-28 20:02 被阅读3417次

    两个app: Test 和 BasicGrammar

    目的:从Test app 中打开 BasicGrammar app内指定的某个页面,并传参数过去:


    BasicGrammar:

    配置info.plist AppDelegate
     func application(app: UIApplication, openURL url: NSURL, options: [String : AnyObject]) -> Bool {
            
            //这里进行判断是哪一个app在打开此app,然后分别进行操作
            let scheme = url.scheme
            //不分大小写比较
            if scheme.caseInsensitiveCompare("OpenAppTest") == .OrderedSame{
            
                //执行跳转,跳转到你想要的页面
                let alert = UIAlertView(title: "\(scheme)", message: "\(url)", delegate: self, cancelButtonTitle: "确认")//iOS, introduced=2.0, deprecated=9.0
                alert.show()
                
                let vc = NextViewController()
                if let navVC = self.window?.rootViewController as? UINavigationController{
                    navVC.pushViewController(vc, animated: true)
                }
                
            
                return true
                
            }
            
            return true
        }
    
    

    Test:

    记得设置info.plist里面的LSApplicationQueriesSchemes,iOS9之后需要,iOS9之后提高了app的安全性,需要给出一个类似白名单的东西,在白名单里面的才能打开app。不然报错: -canOpenURL: failed for URL: "OpenAppTest://mark?id=007" - error: "This app is not allowed to query for scheme OpenAppTest"
    func openAppButton(){
        
            let button = UIButton()
            self.view.addSubview(button)//(必须要先把button加进来,才可以用去写它的布局)erminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'couldn't find a common superview for <UIButton: 0x136682f20; frame = (0 0; 0 0); opaque = NO; layer = <CALayer: 0x136682e70>> and <UIView: 0x136683900; frame = (0 0; 414 736); autoresize = W+H; layer = <CALayer: 0x136682be0>>'*** First throw call stack:
            button.mas_makeConstraints { (make) -> Void in
                make.left.equalTo()(self.view).offset()(20)
                make.right.equalTo()(self.view).offset()(-20)
                make.centerY.equalTo()(self.view)
                make.height.equalTo()(40)
            }
            
            button.setTitle("打开BasicGrammar", forState: .Normal)
            button.setTitleColor(UIColor.cyanColor(), forState: .Normal)
            button.setTitleColor(UIColor.greenColor(), forState: .Highlighted)
            button.titleLabel?.font = UIFont.systemFontOfSize(18)
            
            //设置button边框
            button.layer.borderColor = UIColor.greenColor().CGColor
            button.layer.borderWidth = 2
            button.layer.cornerRadius = 10
            //button.layer.masksToBounds = true
            
            button.addTarget(self, action: "openApp", forControlEvents: .TouchUpInside)//给button添加action
           
        
        }
    
    func openApp(){
        
            
            //记得设置info.plist里面的LSApplicationQueriesSchemes,iOS9之后需要,iOS9之后提高了app的安全性,需要给出一个类似白名单的东西,在白名单里面的才能打开app。不然报错: -canOpenURL: failed for URL: "OpenAppTest://mark?id=007" - error: "This app is not allowed to query for scheme OpenAppTest"
            //OpenAppTest://mark?id=xxxx   (调用BasicGrammar app 拼接参数字符串,拼接的时候就像url那样子  OpenAppTest://标记名字?name=xiaomin&age=23)
            let urlStr = "OpenAppTest://mark?id=" + "007"
            let customUrl = NSURL(string: urlStr)
            
            if UIApplication.sharedApplication().canOpenURL(customUrl!) {
                
                UIApplication.sharedApplication().openURL(customUrl!)
                
            }else{
                
                //提示没有安装 BasicGrammar app
                
            }
        
        }
        
    

    Test app

    Test app

    BasicGrammar app

    BasicGrammar app

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      网友评论

      • 独居焚香:你好,能否直接跳转的支付宝的某个界面。如何跳转到支付宝。
        独居焚香:@NoExcuse 是想打开支付宝的某个界面,并不要执行支付,只是想打开支付宝的某个界面
        NoExcuse:@独居焚香 你是想写支付么?调起支付的界面?
      • syyjay:❤️
      • univer2012:你好,你这用的是约束库可不可以给个链接
        NoExcuse:@univer2012 https://github.com/SnapKit/Masonry

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