iOS字符串比较

作者: 莽原奔马668 | 来源:发表于2017-04-21 15:08 被阅读3032次

在开发的过程中,经常遇到需要比较两个字符串,当然比较的方法很多,下面总结一下比较字符串的方法

一.用C语言比较:strcmp函数
char string1[] = "string!";
char string2[] = "string!";
if(strcmp(string1, string2) == 0)
{
    NSLog(@"1");
}

C中一般都是操作单个字符,不像OC有字符串对象的概念,C中需要操作一串字符,就需要用到数组.

二.用OC语言比较

1.isEqualToString方法:判断字符串是否相等

NSString *astring01 = @"This is a String!";
NSString *astring02 = @"This is a String!";
BOOL result = [astring01 isEqualToString:astring02];
NSLog(@"result:%d",result);

2.compare方法(comparer返回的三种值)

  • NSOrderedSame 判断两者内容是否相同
NSString *astring01 = @"This is a String!";
NSString *astring02 = @"This is a String!";    
BOOL result = [astring01 compare:astring02] == NSOrderedSame;    
NSLog(@"result:%d",result);    
  • NSOrderedAscending 判断两对象值的大小(按字母顺序进行比较,astring02大于astring01为真)
NSString *astring01 = @"This is a String!";
NSString *astring02 = @"this is a String!";
BOOL result = [astring01 compare:astring02] == NSOrderedAscending;    
NSLog(@"result:%d",result);
  • NSOrderedDescending 判断两对象值的大小(按字母顺序进行比较,astring02小于astring01为真)
NSString *astring01 = @"this is a String!";
NSString *astring02 = @"This is a String!";
BOOL result = [astring01 compare:astring02] == NSOrderedDescending;    
NSLog(@"result:%d",result);

3.不考虑大小写比较字符串

  • NSOrderedDescending判断两对象值的大小(按字母顺序进行比较,astring02小于astring01为真
NSString *astring01 = @"this is a String!";
NSString *astring02 = @"This is a String!";
BOOL result = [astring01 caseInsensitiveCompare:astring02] == NSOrderedSame;    
NSLog(@"result:%d",result);     
  • NSCaseInsensitiveSearch:不区分大小写比较 NSLiteralSearch:进行完全比较,区分大小写 NSNumericSearch:比较字符串的字符个数,而不是字符值。
NSString *astring01 = @"this is a String!";
NSString *astring02 = @"This is a String!";
BOOL result = [astring01 compare:astring02
                            options:NSCaseInsensitiveSearch | NSNumericSearch] == NSOrderedSame;    
NSLog(@"result:%d",result);

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网友评论

  • JJJJJJC:您好我想问一下,如果我用 > 来比较两个字符串是怎么比较的?
    比如
    str1 = @“32”,str2 = @“2”
    if (str1>str2) {
    NSLog(@"str1 > str2");
    }else if (str1<str2){
    NSLog(@"str1 < str2");
    }
    我打log发现 输出的是(str1 < str2)
    莽原奔马668:OC语言不支持用“>”比较字符串,如果像你这样字符串都是由数字组成的,可以转化成整型再比较
    str1.integerValue > str2.integerValue

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