LeetCode 9. Palindrome Number 回

作者: singed | 来源:发表于2018-08-14 08:52 被阅读0次

将int转为str后切片比较即可难度不高

class Solution(object):
    def isPalindrome(self, x):
        str(x) == str(x)[::-1]

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将int转为str后切片比较即可难度不高
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Python 3 实现：源代码已上传 Github，持续更新。源代码已上传至 Github，持续更新中。