SwiftUI 使用Link组件 跳转浏览器打开

效果：

struct ContentView: View {
    @State private var progressValue = 0.0
    var body: some View {
        VStack{
            Link("淘宝", destination: URL(string: "https://taobao.com")!)
            Link(destination: /*@START_MENU_TOKEN@*/URL(string: "https://www.apple.com")!/*@END_MENU_TOKEN@*/){
                Image("iconImage")
            }
        }
    }
}