华为OD机试真题2023_Swift_100_猜字谜

解题思路
使用双层循环，外层谜面，内层谜底
1、变序：判断交换顺序后是否相同
2、去重：判断两个字符串去掉重复字符后是否一致
3、如果上面两条都不符合，就添加字符串 "not found"

Swift 解题过程

// 猜字谜
    func HW2023001() {
        // 测试用例
//        let line1 = "conection", line2 = "connection,today"
//        let line1 = "bdni,wooood,bnid", line2 = "bind,wrong,wood"
//        let line1 = "bdni,wooood", line2 = "bind,wrong,wood"
//        let line1 = "like,wooooood", line2 = "bind,wrong,wood"
//        let miMian = line1.components(separatedBy: ",")
//        let miDi = line2.components(separatedBy: ",")
        // 正式代码
        let miMian = String(readLine()!).components(separatedBy: ",")
        let miDi = String(readLine()!).components(separatedBy: ",")
        var res: [String] = []
        for mian in miMian {
            var isFound = false
            for di in miDi {
                // 判断两个字符串排序后是否一样
                if mian.sorted() == di.sorted() {  // 变序
                    res.append(di)
                    isFound = true
                    break
                }else if quchong(mian, di) {  // 去重
                    res.append(di)
                    isFound = true
                    break
                }
            }
            if !isFound { res.append("not found") }
        }
        print(res.joined(separator: ","))
    }
    // 判断两个字符串去重后是否一样
    func quchong(_ mm: String, _ md: String) -> Bool {
        let mmlist = Set(Array(mm)).sorted()
        let mdlist = Set(Array(md)).sorted()
        return mmlist == mdlist ? true : false
    }