This is a demo task.
Write a function:
def solution(A)
that, given an array A of N integers, returns the smallest positive integer (greater than 0) that does not occur in A.
For example, given A = [1, 3, 6, 4, 1, 2], the function should return 5.
Given A = [1, 2, 3], the function should return 4.
Given A = [−1, −3], the function should return 1.
Write an efficient algorithm for the following assumptions:
N is an integer within the range [1..100,000];
each element of array A is an integer within the range [−1,000,000..1,000,000].
这里只考虑前N+1个数,因为缺失的值肯定小于等于N+1。注意不要先用sort(),时间复杂度会增加啊~
def solution(A):
# write your code in Python 3.6
l = [0]*(len(A)+1)
for i in A:
if 1<=i<=len(A)+1:
l[i-1] =1
for i in range(len(A)+1):
if l[i]==0:
return i+1
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