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P02 使用三个线程使得ABC 循环输出十次
心得
- 利用Condition 来控制对哪个类型的锁进行释放。可以达到对3个线程的一个控制。
- 对于线程输出的控制顺序,可以加入一个判断顺序Int.来决定是否轮到该线程运行,不是则继续等待。
代码块
public class P02 {
private static ReentrantLock lock;
public static int ThSum=1; //决定那个线程运行
/*使用三个线程使得ABC 循环输出十次*/
public static void po2(){
lock = new ReentrantLock(true);
Thread t1 = new Thread(new t1(lock));
Thread t2 = new Thread(new t2(lock));
Thread t3 = new Thread(new t3(lock));
t1.start();
t2.start();
t3.start();
}
}
class t1 implements Runnable{
private ReentrantLock lock;
public static Condition conditionA;
public t1(ReentrantLock lock) {
this.lock = lock;
conditionA = lock.newCondition();
}
@Override
public void run() {
try {
for (int i = 1; i <= 10; i++) {
lock.lock();
while (P02.ThSum != 1) { //如果没有该判断顺序,则线程1 可能会再次获得锁。不能确保顺序正确
conditionA.await(); //当还不是该线程输出的时候,释放锁
}
System.out.print("第"+i+"次");
System.out.print('A');
P02.ThSum = 2;
t2.conditionB.signalAll(); //释放第二个线程 唤醒第二个线程
lock.unlock(); //释放锁,是因为最后一次的时候,如果没有释放锁,那么2 3 线程并不能获取到锁。
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
class t2 implements Runnable{
private ReentrantLock lock;
public static Condition conditionB;
public t2(ReentrantLock lock) {
this.lock = lock;
conditionB = lock.newCondition();
}
@Override
public void run() {
try {
for (int i = 0; i < 10; i++) {
lock.lock();
while (P02.ThSum != 2) {
conditionB.await();
}
System.out.print('B');
P02.ThSum = 3;
t3.conditionC.signalAll();
lock.unlock();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
class t3 implements Runnable{
private ReentrantLock lock;
public static Condition conditionC;
public t3(ReentrantLock lock) {
this.lock = lock;
conditionC = lock.newCondition();
}
@Override
public void run() {
try {
for (int i = 0; i < 10; i++) {
lock.lock();
while (P02.ThSum != 3) {
conditionC.await();
}
System.out.println('C');
P02.ThSum = 1;
t1.conditionA.signalAll();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
输出效果
![](https://img.haomeiwen.com/i6212571/ce64c77cf895531d.png)
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