lambda匿名函数

如下示例：

li = [lambda :x for x in range(10)]
print(type(li))
for i in li:
    print( i,i())

结果如下：

<class 'list'>
<function <listcomp>.<lambda> at 0x000000000117A840> 9
<function <listcomp>.<lambda> at 0x000000000117A8C8> 9
<function <listcomp>.<lambda> at 0x000000000117A950> 9
<function <listcomp>.<lambda> at 0x000000000117A9D8> 9
<function <listcomp>.<lambda> at 0x000000000117AA60> 9
<function <listcomp>.<lambda> at 0x000000000117AAE8> 9
<function <listcomp>.<lambda> at 0x000000000117AB70> 9
<function <listcomp>.<lambda> at 0x000000000117ABF8> 9
<function <listcomp>.<lambda> at 0x000000000117AC80> 9
<function <listcomp>.<lambda> at 0x000000000117AD08> 9

li的类型是一个列表，里面的每一个元素都是一个函数,想象中li中函数的返回值应依次是0-9，因为以上代码等价如下：

li = []
for x in range(10):
    def func():
        return x
    # print(func,func())
    li.append(func)

for i in li:
    print(i,i())

但是li中每个元素的返回值都是9，不理解！暂hold！