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python拓扑排序

python拓扑排序

作者: jacke121 | 来源:发表于2017-09-24 19:18 被阅读89次

    class Graph:
    def init(self):
    self.V = []

    class Vertex:
    def init(self, x):
    self.key = x
    self.color = 'white'
    self.d = 10000
    self.f = 10000
    self.pi = None
    self.adj = []
    self.next = None

    class Solution:
    def Dfs(self, G):
    for u in G.V:
    u.color = 'white'
    u.pi = None
    global time
    time = 0
    for u in G.V:
    if u.color == 'white':
    self.DfsVisit(G, u)

    def DfsVisit(self, G, u):
        global time
        time = time + 1
        u.d = time
        u.color = 'gray'
        for v in u.adj:
            if v.color == 'white':
                self.DfsVisit(G, v)
                v.pi = u
        u.color = 'black'
        time = time + 1
        u.f = time
    
    def TopologicalSort(self, G):
        LinkedList = Vertex('#')
        self.Dfs(G)
        G.V.sort(key=lambda v:v.f)
        for v in G.V:
            v.next = LinkedList.next
            LinkedList.next = v
        return LinkedList
    

    if name == 'main':
    undershorts = Vertex('undershorts')
    socks = Vertex('socks')
    pants = Vertex('pants')
    shoes = Vertex('shoes')
    belt = Vertex('belt')
    shirt = Vertex('shirt')
    tie = Vertex('tie')
    jacket = Vertex('jacket')
    watch = Vertex('watch')

    undershorts.adj = [pants, shoes]
    socks.adj = [shoes]
    pants.adj = [belt, shoes]
    shoes.adj = []
    belt.adj = [jacket]
    shirt.adj = [belt, tie]
    tie.adj = [jacket]
    jacket.adj = []
    watch.adj = []
    
    G = Graph()
    G.V = [undershorts,socks,pants,shoes,belt,shirt,tie,jacket,watch]
    
    m = Solution()
    Sort_List = m.TopologicalSort(G)
    p = Sort_List
    while p.next != None:
        print(p.next.key, p.next.f)
        p = p.next

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