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198. House Robber

198. House Robber

作者: 哲哲哥 | 来源:发表于2017-12-08 17:16 被阅读0次

    You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

    Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

    public static int rob2(int[] nums, int begin,int sum) {
            if (begin >= nums.length) {
            
                return sum;
            }
            int sum1=rob2(nums, begin + 2,sum+nums[begin]);
            int sum2=rob2(nums, begin + 1,sum);
            return Math.max(sum1, sum2);
            
        }
    

    这里一定要注意返回的意义要一样,并且选和不选是其实可以参考成一颗二叉树

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