jmeter随机生成11位手机号

方法一  随机数生成方法，使用BeanShell 预处理程序

1、【线程组-添加-后置处理器-BeanShell 预处理程序】

代码如下：

//定义手机号前3位

String[] FirstThreeNumber = {"134","135","136","137","138","139","147","150","152","157","158","159","172","178","182","183","184","187","188","198","130","131","132","145","155","156","166","171","175","176","185","186","166","133","149","153","173","177","180","181","189","199"};

//随机获取前三位手机号的index

int n= (int)(Math.random() * FirstThreeNumber.length);

//获取手机前三位

String yy = FirstThreeNumber[n];

//循环获取手机号后8位

for(int i = 0; i < 8; i++){

    int x = (int)(Math.random() * 9);

    yy = yy + x;

};

vars.put("phone", yy);

2、调用随机数

3、运行查看结果数，随机生成11位数字

方法二   利用时间戳+随机数生成手机号后八位，减少重复（但是手机号前三位只能固定写死）

1、获取时间戳前八位

取时间戳前x位数：${__time(/1【后面带（13-x）个0】,)}  

时间戳前八位：${__time(/100000,)}

2、【线程组-添加-后置处理器-BeanShell 预处理程序】

代码如下：

//${__time(/100000,)}也可由函数助手生成，${__Random(1,100000,)}随机生成数，与时间戳相加，避免重复

phone=${__time(/100000,)}+${__Random(1,100000,)};

//phone是一个整数，这里将其转化为一个字符串并且赋给a

String a=String.valueOf(phone);

//将a设置为变量

vars.put("phone",a);

//在debug sample中可查看phone的取值

vars.get("phone");

3、调用后八位随机数

4、运行查看结果数，随机生成187开头的11位数字