分别打印a与b 加／减／乘／除／幂／商／余数

a = 10

b = 3

print("a+b =",a+b)

print("a-b =",a-b)

print("a*b =",a*b)

print("a/b =",a/b)

print("a**b =",a**b)

print("a/b =",int(a/b))

print("a%b =",a%b)

计算1+2+3+4……+100的和

sum = 0

for i in range(101):

sum+=i

print('第二题结果等于：',sum)

计算1〜100中所有偶数之各

sum = 0

for i in range(0,101,2):

#    print(i)

sum+=i

print('1~100中偶像之和等于：',sum)

打印简书ID中所有数字的和

ID='4a577793b99a'
sum = 0
for i in range(len(ID)):
    if ID[i].isdigit():
        sum+=ID[i]
print("所有数字的和",sum)

将字符串0cd768f4b1a1dac0c512e452726361d9两两分割生成元组及列表

s = '0cd768f4b1a1dac0c512e452726361d9'

t = list(s)

result =[]

for i in range(0,len(t),2):

result.append(t[i]+t[i+1])

print(result)

如何用循环生成下面字典 item={1:'1',2:'2',3:'3'}

item={}

for i in range(1,4):

item[i]='%s'%i

print(item)

打印dict_date中value的年份在1970~1976的key

dict_date = {"Led Zeppelin":1969, "Led Zeppelin II": 1969, "Led Zeppelin III": 1970, "Led Zeppelin IV": 1971, "Houses of the Holy":1973, "Physical Graffiti": 1975, "Presence":1976, "In Through the Out Door":1979, "Coda":1982}

for k in dict_date.keys():

if dict_date[k]>=1970 and dict_date[k]<=1976:

print(dict_date[k])

编写一个用来交换 a 与 b 值的函数

逻辑题，结果是什么？如何分析解答这道题？

list_a = [i for i in range (10) if i % 2]

print(list_a)

#range(10) 即  0~9；对2取模为True,打印出来

编写一个用来交换字典 key 与 value 的函数(重复的放入 value list 中)

def change_num(dict_1):
    s = dict_1.items()
    d = {}
    for x, y in s:
        d.setdefault(y,[]).append(x)
    return d

D =  {"a":1,"b":1,"c":2}
d = change_num(D)

通过代码实现将以上所有代码及结果输出到同一文件中(首行需标注)

from sys import argv
script, file_name, new_file = argv
content = open(file_name)
new = open(new_file, 'w')

o = 'line1: this is copy script file.'
y = content.read()
new.write(o+'\n'+y)