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Android日常错误记录

Android日常错误记录

作者: Jumping_张明 | 来源:发表于2018-12-26 12:35 被阅读0次

环信即时通讯

Q:找不到AsyncTaskCompatl类 NoClassDefFoundError: support/v4/os/AsyncTaskCompat
A:因为AsyncTaskCompat此类已在API26.0.0以上中被弃用了,所以需要更改compileSdkVersion最高26,同理targetSdkVersion和其它依赖也需要适当降低版本。

Service里启动Activity延时问题

Q:Service里监听按键然后启动Activity,大约延时2-3s左右才启动
A:使用延时意图

    intent intent = new Intent(context, AnotherActivity.class);
    intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, intent, 0);
    try {
        pendingIntent.send(); 
    } catch (PendingIntent.CanceledException e) {
        e.printStackTrace();
    }

getSupportFragmentManager()报红

app包下FragmentManager用:
Fragmentmanager fragmentManager=getFragmentManager();
v-4包的FragmentManager用:
FragmentManager fragmentManager=getSupportFragmentManager() 获取
但是getSupportFragmentManager() 有其运用范围,只能在部分activity中运用。当遇到getSupportFragmentManager() 没定义的问题时,修改下activity为FragmentActivity或者AppCompatActivity。

旋转动画的时候会有停顿

<?xml version="1.0" encoding="utf-8"?>
<set xmlns:android="http://schemas.android.com/apk/res/android">
    <rotate
        android:duration="2000"
        android:pivotX="50%"
        android:pivotY="50%"
        android:repeatCount="-1"
        android:fromDegrees="0"
        android:toDegrees="359"  />
</set>
        Animation rotateAnimation = AnimationUtils.loadAnimation(this, R.anim.rotate_anim);
        //解决旋转有停顿
        LinearInterpolator lir = new LinearInterpolator();
        rotateAnimation.setInterpolator(lir);
        mIvLoading.startAnimation(rotateAnimation);

Error: Program type already present: android.support.v4.app.INotificationSideChannel

当项目使用API28对应的是android9.0,当AndroidStudio运行项目的时候出现编译错误:Error: Program type already present: android.support.v4.app.INotificationSideChannel,这意思是v4包冲突了。
首先,查找一下自己的文件里是否存在v4包重复的,搜索之后发现没有出现重复,针对这个问题查看了网上一些资料,发现这个问题是AndroidX版本引起的。有以下两种解决方法:

1、Refactor-->Migrate to AndroidX

2、向gradle.properties添加以下内容:
android.enableJetifier=true
android.useAndroidX=true

Android与AndroidX包重复问题详情可查看这篇文章:https://www.jianshu.com/p/1466ebefe4d0
如果SDK不是28的版本,可在Terminal窗口复制命令gradlew clean build --stacktrace去查看详细信息针对性去解决问题~

zip4j jar包使用中遇到解压文件名字部分出现乱码

ZipFile zipFile = new ZipFile(zipfilenow.getAbsolutePath());
zipFile.setFileNameCharset(getCharset(zipfilenow.getPath()));

/**
     * 判断文件的编码格式
     *
     * @param fileName
     * @return
     */
    public static String getCharset(String fileName) {
        BufferedInputStream bis = null;
        String charset = "GBK";
        byte[] first3Bytes = new byte[3];
        try {
            boolean checked = false;
            bis = new BufferedInputStream(new FileInputStream(fileName));
            bis.mark(0);
            int read = bis.read(first3Bytes, 0, 3);
            if (read == -1)
                return charset;
            if (first3Bytes[0] == (byte) 0xFF && first3Bytes[1] == (byte) 0xFE) {
                charset = "UTF-16LE";
                checked = true;
            } else if (first3Bytes[0] == (byte) 0xFE
                    && first3Bytes[1] == (byte) 0xFF) {
                charset = "UTF-16BE";
                checked = true;
            } else if (first3Bytes[0] == (byte) 0xEF
                    && first3Bytes[1] == (byte) 0xBB
                    && first3Bytes[2] == (byte) 0xBF) {
                charset = "UTF-8";
                checked = true;
            }
            bis.mark(0);
            if (!checked) {
                while ((read = bis.read()) != -1) {
                    if (read >= 0xF0)
                        break;
                    if (0x80 <= read && read <= 0xBF) // 单独出现BF以下的,也算是GBK
                        break;
                    if (0xC0 <= read && read <= 0xDF) {
                        read = bis.read();
                        if (0x80 <= read && read <= 0xBF) // 双字节 (0xC0 - 0xDF)
                            // (0x80 - 0xBF),也可能在GB编码内
                            continue;
                        else
                            break;
                    } else if (0xE0 <= read && read <= 0xEF) {// 也有可能出错,但是几率较小
                        read = bis.read();
                        if (0x80 <= read && read <= 0xBF) {
                            read = bis.read();
                            if (0x80 <= read && read <= 0xBF) {
                                charset = "UTF-8";
                                break;
                            } else
                                break;
                        } else
                            break;
                    }
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            if (bis != null) {
                try {
                    bis.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }

        return charset;
    }

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