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Leetcode 129. Sum Root to Leaf N

Leetcode 129. Sum Root to Leaf N

作者: persistent100 | 来源:发表于2017-12-18 15:49 被阅读0次

    Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.
    An example is the root-to-leaf path 1->2->3 which represents the number 123.
    Find the total sum of all root-to-leaf numbers.
    For example,

        1
       / \
      2   3
    

    The root-to-leaf path 1->2 represents the number 12.
    The root-to-leaf path 1->3 represents the number 13.
    Return the sum = 12 + 13 = 25.

    分析

    从根到叶组成一系列的数,求之和。树的问题最好还是使用递归,到叶子节点时候计算总和跳出循环,如果有左右节点,依次计算之后返回总的和。

    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     struct TreeNode *left;
     *     struct TreeNode *right;
     * };
     */
    int sum(struct TreeNode *root ,int temp,int answer)
    {
        if(root==NULL)return 0;
        temp=temp*10+root->val;
        if(root->left==NULL&&root->right==NULL)
        {
            answer+=temp;
            return answer;
        }
        if(root->left!=NULL)
            answer=sum(root->left,temp,answer);
        if(root->right!=NULL)
            answer=sum(root->right,temp,answer);
        return answer;
    }
    int sumNumbers(struct TreeNode* root) {
        return sum(root,0,0);
    }
    

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