Leetcode 435. Non-overlapping In

文章作者：Tyan
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1. Description

Non-overlapping Intervals

2. Solution

class Solution:
    def eraseOverlapIntervals(self, intervals):
        count = 0
        if len(intervals) < 2:
            return count
        intervals.sort(key=lambda interval: interval[1])
        overlap = intervals[0]
        for index in range(1, len(intervals)):
            if overlap[1] > intervals[index][0]:
                count += 1
            else:
                overlap = intervals[index]

        return count

Reference

1. https://leetcode.com/problems/non-overlapping-intervals/