题目：
将DOM节点元素转换成JSON的格式
例如
<div class="root">
<div class="child1"><p></p></div>
<span></span>
<div><div><p></p></div></div>
<p></p>
</div>
转换显示成(简写，大致表达个意思)：
{"tagName":"DIV", className="root", childs:[{"tagName":"DIV", className="root",childs:[]}]}
乍一看上去并不是很难，递归，找出各个节点的child节点即可，可真正当场写出代码还是需要锻炼锻炼，反正我当时没写出来，课后补习：
试一试：http://jsrun.net/VPaKp/edit
HTML File:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=, initial-scale=">
<meta http-equiv="X-UA-Compatible" content="">
<title></title>
</head>
<body>
<div class="root">
<div class="child1"><p></p></div>
<span class="span1"><span></span></span>
<div><div><p class="p1"></p></div></div>
<p><span></span></p>
</div>
</body>
</html>
JS File:
function convertToJson() {
const root = document.getElementsByClassName('root')[0];
const output = new Object();
output.tagName = root.tagName;
output.className = root.className;
output.childs = getChilds(root);
console.log(JSON.stringify(output));
}
function getChilds(node) {
const childs = node.children;
const result = new Array();
if(!childs || childs.length === 0) return result;
for (const child of childs) {
const childOutput = new Object();
childOutput.tagName = child.tagName;
childOutput.className = child.className;
childOutput.childs = getChilds(child);
result.push(childOutput);
}
return result;
}
convertToJson();
运行结果：
{"tagName":"DIV","className":"root","childs":[{"tagName":"DIV","className":"child1","childs":[{"tagName":"P","className":"","childs":[]}]},{"tagName":"SPAN","className":"span1","childs":[{"tagName":"SPAN","className":"","childs":[]}]},{"tagName":"DIV","className":"","childs":[{"tagName":"DIV","className":"","childs":[{"tagName":"P","className":"p1","childs":[]}]}]},{"tagName":"P","className":"","childs":[{"tagName":"SPAN","className":"","childs":[]}]}]}
随便找了一个格式化的网站把json字符串格式化显示下：
在对比下HTML文件目录：
<div class="root">
<div class="child1"><p></p></div>
<span class="span1"><span></span></span>
<div><div><p class="p1"></p></div></div>
<p><span></span></p>
</div>
就是这么回事。目前就是想到这个方法了，至于是不是最优就不得而知啦~
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