胖博士今天分享的题目如下:
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)(2014年第三届海峡杯五年级决赛第9题)
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分析:=(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23)×(0.12+0.23)-0.34×(0.12+0.23)
=(1+0.12+0.23)×(0.12+0.23+0.34-0.12-0.34)-0.34×(0.12+0.23)
=0.34
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太复杂了怎么办?换元法,
设1+0.12+0.23=A,0.12+0.23+0.34=B
则原式=A×B-(A+0.34)×(B-0.34)
=AB-(AB+0.34B-0.34A-0.342)
=AB-AB+0.34(A-B+0.34)
=0.34×(1+0.12+0.23-0.12-0.23-0.34+0.34)
=0.34×1
=0.34
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视频讲解参见
https://www.ixigua.com/i6829928297288172044/
大家可以做完后再看解答哦。
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