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xcode 创建脚本,打包时删除动态库的模拟机架构

xcode 创建脚本,打包时删除动态库的模拟机架构

作者: Jason_风筝 | 来源:发表于2019-02-28 23:16 被阅读0次

    ios8 之后, 苹果开放了动态库.也就是我们可以打包动态库, 但动态库如果上传到iTunes 是不能包含模拟机架构的. 所以就要求我们在打包时先删除模拟机的架构.
    可以添加一个run 脚本帮我们完成, 参考网址

    下图就是脚本


    Shell: /bin/sh

    APP_PATH="${TARGET_BUILD_DIR}/${WRAPPER_NAME}"
    
    # This script loops through the frameworks embedded in the application and
    # removes unused architectures.
    find "$APP_PATH" -name '*.framework' -type d | while read -r FRAMEWORK
    do
        FRAMEWORK_EXECUTABLE_NAME=$(defaults read "$FRAMEWORK/Info.plist" CFBundleExecutable)
        FRAMEWORK_EXECUTABLE_PATH="$FRAMEWORK/$FRAMEWORK_EXECUTABLE_NAME"
        echo "Executable is $FRAMEWORK_EXECUTABLE_PATH"
    
        EXTRACTED_ARCHS=()
    
        for ARCH in $ARCHS
        do
            echo "Extracting $ARCH from $FRAMEWORK_EXECUTABLE_NAME"
            lipo -extract "$ARCH" "$FRAMEWORK_EXECUTABLE_PATH" -o "$FRAMEWORK_EXECUTABLE_PATH-$ARCH"
            EXTRACTED_ARCHS+=("$FRAMEWORK_EXECUTABLE_PATH-$ARCH")
        done
    
        echo "Merging extracted architectures: ${ARCHS}"
        lipo -o "$FRAMEWORK_EXECUTABLE_PATH-merged" -create "${EXTRACTED_ARCHS[@]}"
        rm "${EXTRACTED_ARCHS[@]}"
    
        echo "Replacing original executable with thinned version"
        rm "$FRAMEWORK_EXECUTABLE_PATH"
        mv "$FRAMEWORK_EXECUTABLE_PATH-merged" "$FRAMEWORK_EXECUTABLE_PATH"
    
    done
    

    该脚本将查看你构建的应用程序的Frameworks文件夹~~ end

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