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66. Plus One

66. Plus One

作者: SilentDawn | 来源:发表于2018-05-31 08:55 被阅读0次

    Problem

    Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

    The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

    You may assume the integer does not contain any leading zero, except the number 0 itself.

    Example

    Input: [1,2,3]
    Output: [1,2,4]
    Explanation: The array represents the integer 123.
    
    Input: [4,3,2,1]
    Output: [4,3,2,2]
    Explanation: The array represents the integer 4321.
    

    Code

    static int var = [](){
        std::ios::sync_with_stdio(false);
        cin.tie(NULL);
        return 0;
    }();
    class Solution {
    public:
        vector<int> plusOne(vector<int>& digits) {
            int i = digits.size()-1;
            digits[i] += 1;
            while(digits[i]==10 && i>0){
                digits[i] = 0;
                digits[i-1] += 1;
                i--;
            }
            if(digits[0]==10){
                digits[0] = 0;
                digits.insert(digits.begin(),1);
            }
            return digits;
        }
    };
    

    Result

    66. Plus One.png

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