背景
查找以【,2018】开头的记录;
LIKE
WHERE m.path LIKE ',2018%'
SUBSTR
WHERE SUBSTR(m.path,1,5) = ',2018'
- 列名;
- 起始位置,从1开始;
- 结束位置;
查找以【,2018】开头的记录;
WHERE m.path LIKE ',2018%'
WHERE SUBSTR(m.path,1,5) = ',2018'
本文标题:mysql使用substr替代like
本文链接:https://www.haomeiwen.com/subject/oodaeftx.html
网友评论