线性插值 np.interp

计算得出0-299这300个数的线性插值

def interpNumList(num):
"""
计算线性插值列表
:param NumList:
:return:
"""
interpList = []

NumList = [i for i in range(num + 1)]

startList = [0.2, 0.4, 0.6, 0.8]
interpList.extend(startList)

startListCopy = startList.copy()

for i in range(len(NumList)):

    start = i
    mid = start + 1
    end = start + 2

    if end <= len(NumList) - 1:

        x1 = np.array([NumList[start], NumList[mid]])
        y1 = np.array([NumList[mid], NumList[end]])
        res = list(np.interp(startListCopy, x1, y1))

        interpList.extend(res)

        startListCopy = res

    else:
        break

resultList = sorted(interpList + NumList[:-1], reverse=False)

return resultList

ok, 300个数字线性插值完成！