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36. 有效的数独

36. 有效的数独

作者: Abeants | 来源:发表于2022-03-26 22:01 被阅读0次

    请你判断一个 9 x 9 的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。

    数字 1-9 在每一行只能出现一次。
    数字 1-9 在每一列只能出现一次。
    数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)

    注意:

    • 一个有效的数独(部分已被填充)不一定是可解的。
    • 只需要根据以上规则,验证已经填入的数字是否有效即可。
    • 空白格用 '.' 表示。

    示例 1:



    输入:board =
    [["5","3",".",".","7",".",".",".","."]
    ,["6",".",".","1","9","5",".",".","."]
    ,[".","9","8",".",".",".",".","6","."]
    ,["8",".",".",".","6",".",".",".","3"]
    ,["4",".",".","8",".","3",".",".","1"]
    ,["7",".",".",".","2",".",".",".","6"]
    ,[".","6",".",".",".",".","2","8","."]
    ,[".",".",".","4","1","9",".",".","5"]
    ,[".",".",".",".","8",".",".","7","9"]]
    输出:true

    示例 2:
    输入:board =
    [["8","3",".",".","7",".",".",".","."]
    ,["6",".",".","1","9","5",".",".","."]
    ,[".","9","8",".",".",".",".","6","."]
    ,["8",".",".",".","6",".",".",".","3"]
    ,["4",".",".","8",".","3",".",".","1"]
    ,["7",".",".",".","2",".",".",".","6"]
    ,[".","6",".",".",".",".","2","8","."]
    ,[".",".",".","4","1","9",".",".","5"]
    ,[".",".",".",".","8",".",".","7","9"]]
    输出:false
    解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。

    提示:
    board.length == 9
    board[i].length == 9
    board[i][j] 是一位数字(1-9)或者 '.'

    来源:力扣(LeetCode)
    链接:https://leetcode-cn.com/problems/valid-sudoku
    著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

    解题思路及方法

    一次遍历,建立两个二维数组记录每行每列数字的出现次数,例如:
    rows[0][1]=1,代表第一行数字2的出现次数为1;
    如果每行每列某个数字出现次数超过一次,就代表这是一个不合法的数独。同理,建立一个三维数组来记录每个子九宫格数字出现次数。

    class Solution {
        public boolean isValidSudoku(char[][] board) {
            int[][] rows = new int[9][9];
            int[][] clns = new int[9][9];
            int[][][] sons = new int[3][3][9];
    
            for (int i = 0; i < 9; i++) {
                for (int j = 0; j < 9; j++) {
                    char ch = board[i][j];
                    if (ch == '.') continue;
                    // 记录每行每列数字出现次数
                    int idx = ch - '0' - 1;
                    rows[i][idx]++;
                    clns[idx][j]++;
                    // 记录子九宫格数字出现次数
                    sons[i / 3][j / 3][idx]++;
                    // 判定数字出现次数
                    if (rows[i][idx] > 1 || clns[idx][j] > 1 || sons[i / 3][j / 3][idx] > 1) return false;
                }
            }
            
            return true;
        }
    }
    

    结果如下:

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