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选读SQL经典实例笔记10_高级查询

选读SQL经典实例笔记10_高级查询

作者: 躺柒 | 来源:发表于2023-07-19 07:00 被阅读0次
    选读SQL经典实例笔记10_高级查询.png

    1. 结果集分页

    1.1. 只有做过了排序,才有可能准确地从结果集中返回指定区间的记录

    1.2. DB2

    1.3. Oracle

    1.4. SQL Server

    1.5. sql

    select sal
      from (
    select row_number() over (order by sal) as rn,
           sal
      from emp
           ) x
     where rn between 1 and 5
    SAL
    ----
     800
    950
    1100
    1250
    1250
    

    1.5.2. sql

    select sal
      from (
    select row_number() over (order by sal) as rn,
           sal
      from emp
           ) x
     where rn between 6 and 10
    SAL
    -----
     1300
     1500
     1600
     2450
     2850
    

    1.6. PostgreSQL

    1.7. MySQL

    1.8. sql

    select sal
      from emp
     order by sal limit 5 offset 0
    SAL
    ------
       800
       950
      1100
      1250
      1250
    

    1.8.2. sql

     select sal
      from emp
     order by sal limit 5 offset 5
    SAL
    -----
     1300
     1500
     1600
     2450
     2850
    

    2. 跳过n行记录

    2.1. 获得第一个员工、第三个员工,等等

    2.2. DB2

    2.3. Oracle

    2.4. SQL Server

    2.5. 使用窗口函数ROW_NUMBER OVER为每一行分配一个序号

    select ename
        from (
      select row_number() over (order by ename) rn,
             ename
        from emp
             ) x
       where mod(rn,2) = 1
    

    2.6. PostgreSQL

    2.7. MySQL

    2.8. 使用标量子查询

    select x.ename
        from (
      select a.ename,
             (select count(*)
                from emp b
               where b.ename <= a.ename) as rn
        from emp a
             )x
       where mod(x.rn,2) = 1
    

    3. 提取最靠前的n行记录

    3.1. 基于某种排序方式从结果集中提取出限定数目的记录

    3.2. DB2

    3.3. Oracle

    3.4. SQL Server

    3.5. DENSE_RANK函数

    select ename,sal
       from (
     select ename, sal,
            dense_rank() over (order by sal desc) dr
       from emp
            ) x
      where dr <= 5
    

    3.6. PostgreSQL

    3.7. MySQL

    3.8. 使用标量子查询

    select ename,sal
        from (
      select (select count(distinct b.sal)
                from emp b
               where a.sal <= b.sal) as rnk,
              a.sal,
              a.ename
        from emp a
             )
       where rnk <= 5
    

    4. 对结果排序

    4.1. DB2

    4.2. Oracle

    4.3. SQL Server

    4.4. 窗口函数DENSE_RANK OVER

    select dense_rank() over(order by sal) rnk, sal
       from emp
    

    4.5. PostgreSQL

    4.6. MySQL

    4.7. 标量子查询

    select (select count(distinct b.sal)
                from emp b
               where b.sal <= a.sal) as rnk,
             a.sal
        from emp a
    

    5. 删除重复项

    5.1. DB2

    5.2. Oracle

    5.3. SQL Server

    5.4. 窗口函数ROW_NUMBER OVER

    select job
        from (
      select job,
             row_number()over(partition by job order by job) rn
        from emp
             )x
       where rn = 1
    

    5.5. PostgreSQL

    5.6. MySQL

    5.7. sql

    select distinct job
      from emp
    select job
      from emp
     group by job
    

    5.7.3. GROUP BY和DISTINCT是两个非常不同的子句,它们是不可互换的

    6. 骑士值

    6.1. 返回一个结果集,其中包括每个员工的姓名、部门、工资、入职时间以及每一个部门里最近入职的那个员工的工资

    6.2. DB2

    6.3. SQL Server

    6.4. 窗口函数MAX OVER

    select deptno,
            ename,
            sal,
            hiredate,
            max(latest_sal)over(partition by deptno) latest_sal
       from (
     select deptno,
            ename,
            sal,
            hiredate,
            case
              when hiredate = max(hiredate)over(partition by deptno)
              then sal else 0
            end latest_sal
       from emp
            ) x
      order by 1, 4 desc
    

    6.5. Oracle

    select deptno,
            ename,
            sal,
            hiredate,
            max(sal)
              keep(dense_rank last order by hiredate)
              over(partition by deptno) latest_sal
       from emp
      order by 1, 4 desc
    

    6.6. PostgreSQL

    6.7. MySQL

    6.8. 两层嵌套的标量子查询

    select e.deptno,
             e.ename,
             e.sal,
             e.hiredate,
             (select max(d.sal)
                from emp d
               where d.deptno  = e.deptno
                 and d.hiredate =
                     (select max(f.hiredate)
                        from emp f
                       where f.deptno = e.deptno)) as latest_sal
        from emp e
       order by 1, 4 desc
    

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