解决Illegal hex characters in escape (%) pattern - For input string
public class EscapeUnescape {
/**
* escape 编码
* @param src
* @return
*/
public static String escape(String src) {
int i;
char j;
StringBuffer buffer = new StringBuffer();
buffer.ensureCapacity(src.length() * 6);
for (i = 0; i < src.length(); i++) {
j = src.charAt(i);
if (Character.isDigit(j) || Character.isLowerCase(j)
|| Character.isUpperCase(j))
buffer.append(j);
else if (j < 256) {
buffer.append("%");
if (j < 16)
buffer.append("0");
buffer.append(Integer.toString(j, 16));
} else {
buffer.append("%u");
buffer.append(Integer.toString(j, 16));
}
}
return buffer.toString();
}
/**
* unescape 解码
* @param src
* @return
*/
public static String unescape(String src) {
StringBuffer buffer = new StringBuffer();
buffer.ensureCapacity(src.length());
int lastPos = 0, pos = 0;
char ch;
while (lastPos < src.length()) {
pos = src.indexOf("%", lastPos);
if (pos == lastPos) {
if (src.charAt(pos + 1) == 'u') {
ch = (char) Integer.parseInt(src.substring(pos + 2, pos + 6), 16);
buffer.append(ch);
lastPos = pos + 6;
} else {
ch = (char) Integer.parseInt(src.substring(pos + 1, pos + 3), 16);
buffer.append(ch);
lastPos = pos + 3;
}
} else {
if (pos == -1) {
buffer.append(src.substring(lastPos));
lastPos = src.length();
} else {
buffer.append(src, lastPos, pos);
lastPos = pos;
}
}
}
return buffer.toString();
}
}
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